W^4+81=81w^2

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Solution for W^4+81=81w^2 equation: 



^4+81=81W^2

We move all terms to the left:

^4+81-(81W^2)=0

We add all the numbers together, and all the variables

-81W^2=0

a = -81; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-81)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$W=\frac{-b}{2a}=\frac{0}{-162}=0$

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